Practice Solutions

1. $\frac{x}{7}–11=–1$

$$\begin{gathered} \frac{\overline{)x}}{7}–11=–1 \\ ÷7 \uparrow ·7 \\ –11 \uparrow +11 \end{gathered}$$

2. $4x+\frac{1}{4}=7$

$$\begin{gathered} 4\overline{)x}+\frac{1}{4}=7 \\ ·4 \uparrow ÷4 \\ –\frac{1}{4}\uparrow +\frac{1}{4} \end{gathered}$$

3. $5x+8=45$

$$\begin{gathered} 5\overline{)x}+8=45 \\ ·5 \uparrow ÷5 \\ +8 \uparrow –8 \end{gathered}$$

4. $Ax+P=G$

$$\begin{gathered} A\overline{)x}+P=G \\ ·A \uparrow ÷A \\ +P\uparrow –P \end{gathered}$$

5. $–\frac{2}{3}x+\frac{4}{3}=–3$

$$\begin{gathered} –\frac{2}{3}\overline{)x}+\frac{4}{3}=–3 \\ ·\left(–\frac{2}{3}\right)\uparrow ·\left(–\frac{3}{2}\right) \\ +\frac{4}{3}\uparrow –\frac{4}{3} \end{gathered}$$

6. $2=9x+\frac{4}{5}$

$$\begin{gathered} 2=9\overline{)x}+\frac{4}{5} \\ ·9 \uparrow ÷9 \\ +\frac{4}{5}\uparrow –\frac{4}{5} \end{gathered}$$

7. $\frac{x}{6}+3=11$

$$\begin{gathered} \frac{\overline{)x}}{6}+3=11 \\ ÷6\uparrow ·6 \\ +3 \uparrow –3 \end{gathered}$$

8. $\frac{x}{C}–B=Q$

$$\begin{gathered} \frac{\overline{)x}}{C}–B=Q \\ ÷C \uparrow ·C \\ –B \uparrow +B \end{gathered}$$

9. $5–1x=–10$

$$\begin{gathered} 5–1\overline{)x}=–10 \\ ·\left(–1\right)\uparrow ÷\left(–1\right) \\ +5 \uparrow –5 \end{gathered}$$

10. $\frac{7}{4}–\frac{5}{6}x=8$

$$\begin{gathered} \frac{7}{4}–\frac{5}{6}\overline{)x}=8 \\ ·\left(–\frac{5}{6}\right)\uparrow ·\left(–\frac{6}{5}\right) \\ +\frac{7}{4} \uparrow –\frac{7}{4} \end{gathered}$$

11. $\frac{x+8}{9}=3$

$$\begin{gathered} \frac{\overline{)x}+8}{9}=3 \\ +8\uparrow –8 \\ ÷9\uparrow ·9 \end{gathered}$$

12. $\frac{x–D}{5}=Q$

$$\begin{gathered} \frac{\overline{)x}–D}{5}=Q \\ –D\uparrow +D \\ ÷5 \uparrow ·5 \end{gathered}$$