Practice Solutions

1. $\frac{\overline{)x}}{7}–11=–1$

$$\begin{gathered} ÷7 \uparrow ·7 \\ –11 \uparrow +11 \end{gathered}$$

2. $4\overline{)x}+\frac{1}{4}=7$

$$\begin{gathered} ·4 \uparrow ÷4 \\ –\frac{1}{4}\uparrow +\frac{1}{4} \end{gathered}$$

3. $5\overline{)x}+8=45$

$$\begin{gathered} ·5 \uparrow ÷5 \\ +8 \uparrow –8 \end{gathered}$$

4. $A\overline{)x}+P=G$

$$\begin{gathered} ·A \uparrow ÷A \\ +P\uparrow –P \end{gathered}$$

5. $–\frac{2}{3}\overline{)x}+\frac{4}{3}=–3$

$$\begin{gathered} ·\left(–\frac{2}{3}\right)\uparrow ·\left(–\frac{3}{2}\right) \\ +\frac{4}{3}\uparrow –\frac{4}{3} \end{gathered}$$

6. $2=9\overline{)x}+\frac{4}{5}$

$$\begin{gathered} ·9 \uparrow ÷9 \\ +\frac{4}{5}\uparrow –\frac{4}{5} \end{gathered}$$

7. $\frac{\overline{)x}}{6}+3=11$

$$\begin{gathered} ÷6\uparrow ·6 \\ +3 \uparrow –3 \end{gathered}$$

8. $\frac{\overline{)x}}{C}–B=Q$

$$\begin{gathered} ÷C \uparrow ·C \\ –B \uparrow +B \end{gathered}$$

9. $5–1\overline{)x}=–10$

$$\begin{gathered} ·\left(–1\right)\uparrow ÷\left(–1\right) \\ +5 \uparrow –5 \end{gathered}$$

10. $\frac{7}{4}–\frac{5}{6}\overline{)x}=8$

$$\begin{gathered} ·\left(–\frac{5}{6}\right)\uparrow ·\left(–\frac{6}{5}\right) \\ +\frac{7}{4} \uparrow –\frac{7}{4} \end{gathered}$$

11. $\frac{\overline{)x}+8}{9}=3$

$$\begin{gathered} +8\uparrow –8 \\ ÷9\uparrow ·9 \end{gathered}$$

12. $\frac{\overline{)x}–D}{5}=Q$

$$\begin{gathered} –D\uparrow +D \\ ÷5 \uparrow ·5 \end{gathered}$$