Practice Solutions

1. $y=3x+2$

$$\begin{gathered} y=3\left(–1\right)+2=–3+2=–1 \\ y=3\left(0\right)+2=0+2=2 \\ y=3\left(1\right)+2=3+2=5 \end{gathered}$$

2. $y=\frac{1}{4}x$

$$\begin{gathered} y=\frac{1}{4}\left(–4\right)=–1 \\ y=\frac{1}{4}\left(0\right)=0 \\ y=\frac{1}{4}\left(4\right)=1 \end{gathered}$$

3. $y=–x+3$

$$\begin{gathered} y=–\left(–1\right)+3=1+3=4 \\ y=–\left(0\right)+3=0+3=3 \\ y=–\left(1\right)+3=–1+3=2 \end{gathered}$$

4. $y=\frac{2}{3}x+2$

$$\begin{gathered} y=\frac{2}{3}\left(–3\right)+2=–2+2=0 \\ y=\frac{2}{3}\left(0\right)+2=0+2=2 \\ y=\frac{2}{3}\left(3\right)+2=2+2=4 \end{gathered}$$

5. $y=–\frac{5}{4}x–1$

$$\begin{gathered} y=–\frac{5}{4}\left(–4\right)–1=5–1=4 \\ y=–\frac{5}{4}\left(0\right)–1=0–1=–1 \\ y=–\frac{5}{4}\left(4\right)–1=–5–1=–6 \end{gathered}$$

6. $y=–12x–3$

$$\begin{gathered} y=–12\left(–1\right)–3=12–3=9 \\ y=–12\left(0\right)–3=0–3=–3 \\ y=–12\left(1\right)–3=–12–3=–15 \end{gathered}$$