Targeted Review Solutions

Find the inverse of the function.

  1.  fx=3x2

 y=3x2 x=3y2 xy2=3  y2=3x y=3x+2

 f1x=3x+2 

  1. gx=x+3 

 y=x+3  x2=y+32  x2=y+3 y=x23

g1x=x23 

Evaluate when x = –5.

  1. 2x+9 

25+9 24

16

  1. x8+x 

58+5 53

–125

Evaluate when x = –3.

  1. 5x53x 

53533 1535011251 

1125 

  1. 23xxx 

233332333·133 3323·133278·127

18

Write the equation, given the verbal description.

  1. A square root function translated 2 units right and one unit up from the parent function

 a=1, h=2, k=1 y=axh+k

 y=x2+1

  1. A quadratic function reflected across the x-axis, translated up 5 units and left 8 units

 a=1, h=8, k=5 y=axh2+k

 y=x+82+5

Multiple Choice

B

  1. Simplify 5x7y63 using rational exponents.
  1. x2y25x3

  2. 513x213y2

  3. 513x73y63

  4. cannot be simplified

Note
  1. This option is the correct answer in radical form.
  2. This option does not have simplified exponents.

C

  1. Simplify: i67
  1. i

  2. 1

  3. i

  4. –1

     

    67÷4=16 R3i416 ·i31·ii

Note
  1. This option is the solution when the remainder is one.
  2. This option is the solution when there is no remainder.
  3. This option is the solution when the remainder is two.

B

  1. Simplify: a5b4bc2ac2
  1. a3b4

  2. a3b5

  3. a3c3b5

  4. 1a10 b5 c4 

     

    a5b4a2c2bc2a52b14=a3b5

Note
  1. This option did not properly combine the exponent of the variable b.
  2. This option incorrectly simplifies the exponent –2 out of the expression.
  3. This option multiplies instead of adding terms with the same base.

D

  1. Simplify: 2x3y4
  1. 2x12y4

  2. 8x12y4

  3. 16x7y5

  4. 16x12y4

     

    24 x3·4 y416x12y4

Note
  1. This option did not distribute the exponent to the coefficient.
  2. This option multiplied 2 and 4, instead of 24.
  3. This option added the exponents instead of multiplying.
Problem 1 2 3 4 5 6 7 8 9 10 11 12
Origin L19 L19 L18 L18 L11 L15 A1 A1

L = Lesson in this level, A1 = Algebra 1: Principles of Secondary Mathematics

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