Practice 1 Solutions

The approximate value of the log is between which two integers?

  1. log 154

10x=154102=100103=1000

Between 2 and 3

Note

Q: To which integer is log 154 closer? Explain.

A: Log 154 is closer to 2 since 154 is closer to 100 than 1000.

  1. log 4

10x=4100=1101=10

Between 0 and 1

  1. log 6438

10x=6438103=1000104=10000

Between 3 and 4

  1. log 125

10x=125101=110102=1100

Between –2 and –1

For problems 5–8:

    1. Write the log in terms of X and Y when log 2=X and log 3=Y.
    2. Calculate the approximate value of the log when log 20.301 and log 30.4771.
  1. log 108

log 108=log 22·33=log 22+log 33

  1. =2log 2+3log 3=2(X)+3(Y)=2X+3Y
  2. 2(0.301)+3(0.4771)2.0333
  1. 2X+3Y
  2. 2.0333
  1. log 96

log 96=log (25·3)=log 25+log 3

  1. =5log 2+log 3=5(X)+(Y)=5X+Y
  2. 5(0.301)+(0.4771)1.9821
  1. 5X+Y
  2. 1.9821
  1. log 162

log 162=log 2·34=log 2+log 34

  1. =log 2+4log 3=(X)+4(Y)=X+4Y
  2. (0.301)+4(0.4771)2.2094
  1. X+4Y
  2. 2.2094
  1. log 144

log 144=log 24·32=log 24+log 32

  1. =4log 2+2log 3=4(X)+2(Y)=4X+2Y
  2. 4(0.301)+2(0.4771)2.1582
  1. 4X+2Y
  2. 2.1582

Solve. Write the answer as a logarithm and as a number to four decimal places.

  1. 6x=30

log 6x=log 30xlog 6=log 30

x=log 30log 61.8982

  1. 81x3=15

log 81x3=log 15x3log 81=log 15x3=log 15log 81

x=log 15log 81+33.6162

Note

When the power contains an expression, use parentheses to ensure you correctly complete the steps of solving for the variable.

  1. 253x+1=520

log 253x+1=log 5203x+1log 25=log 5203x+1=log 520log 253x=log 520log 251

x=log 5203log 25130.3143

Note

Remember to divide every term by 3 when solving for x.

  1. 72x=490

log 72x=log 4902xlog 7=log 4902x=log 490log 7

x=log 4902log 71.5916

  1. 2x=56

log 2x=log 56xlog2=log56

x=log56log25.8074

  1. 32x+1=12

log 32x+1=log 12x+1log 32=log 12x+1=log 12log 32

x=log 12log3210.2830

Write with common logs using the Change of Base Rule.

Note

Problems 15–17

If you need more practice, you can also evaluate these expressions using technology. Because the directions do not tell you to round, it is not necessary to use 4 decimal places.

  1. log594

log 94log 5

4log 9log 5

  1. log311x

log 11xlog 3

log 11+log xlog 3

  1. log26+log34

log 6log 2+log 4log 3

Solve. Write as a common log.

  1. 7x+23=84

log 7x+23=log 84x+23log 7=log 843x+23=log 84log 73x+2=3log 84log 7

x=3log 84log 72

  1. 24x=13

log 24x=log 134xlog 2=log 134x=log 13log 21x=log 13log 241

x=log 13log 2+4

  1. 15x7=25

log 15x7=log 25x7log 15=log 257x7=log 25log 157

x=7log 25log 15

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