Checkpoint: Evaluating Functions Solution

Evaluate j(x1) for j(x)=x32x.

 jx1=x32x jx1=x132x1 jx1=x1x22x+12x+2 jx1=x32x2+xx2+2x12x+2  jx1=x33x2+x+1

Note

Q: With what will x be replaced in the function?

A: x – 1

 

Show your work to avoid errors. You are familiar with substitution and need to work carefully to ensure the correct answers.

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