Checkpoint: Graphing Hyperbolas Solution

Graph.

$x^{2} - \frac{y^{2}}{16} = 1$

$(0, 0) a = 1 b = 4 m = \pm 4$

Note

Q: What are the slopes of the asymptotes?
A: 4 and –4 

Q: Is the transverse axis horizontal or vertical? Why?
A: The transverse axis is horizontal because the branches open left and right.