Practice 1 Solutions

Determine if the following are polynomials. If so, classify by degree and number of terms.

  1. 3x2y+2xy4

Yes, this is a third degree polynomial.
1st term exp:
2 + 1 = 3
2nd term: 1 + 1 = 2
3rd term: 0

Note

Q: How do you find the degree when the expression contains more than one variable?
A: Add the degree (exponents) of all of the variables.

  1. x4y2+5x+1

No, this is not a polynomial because the first term has a negative exponent.

  1. 2x2+4xxy

No, this is not a polynomial because xy is under a radical.

  1. x5+5x4+10x3+10x2+5x+1

Yes, this is a 5th degree polynomial.
1st term: largest exponent: 
5

Quintic polynomial with 6 terms

Simplify. Write answers in standard form.

  1. x2xy+7x+1x1

x3y+7x2x21x3y+7x2x2+1

x3y+6x2+1

Note

Q: What property allows you to multiply binomials together?
A: The distributive property

  1. ab+2ab3ab+4

a2b23ab+2ab6ab+4

a2b22ab2

  1. g+5g23g+2

g33g2+2g+5g215g+10

g3+2g213g+10

  1. 2xy7x2y23xx2y2+5

14x3y24xy3x3y215x

11x3y24xy15x

Note

Q: What is the degree of the simplified polynomial? Explain.
A: Degree 5, because 3+2=5.

  1. k+2k2+k+3k3

k24+k29

2k213

  1. 2r+1r2+4r2

2r3+8r24r+r2+4r2

2r3+9r22

Note

Q: Why is it not possible to combine terms with different degrees?
A: Because they are not like terms and only like terms can be added.

Factor completely.

Note

Problems 11-16
Q: What is the first step when factoring?
A: Determine if there is a GCF.

  1. 3x2y25xy12

3xy+4xy3

  1. 4a2b24a29b2+9

4a2b219b214a29b21

2a+32a3b+1b1

Note

Q: What special product occurs in this polynomial?
A: A difference of two squares

  1. 5m2+70m+245

5m2+14m+49

5m+72

Note

Q: What special product occurs in this polynomial?
A: A perfect square trinomial

  1. 4x226x+30

22x213x+15

22x3x5

  1. 35q48q33q2

q235q28q3

q25q+17q3

  1. 2xy2+8x9y236

2xy2+49y2+4

2x9y2+4

Factor the sum or difference of cubes completely.

Note

Problems 17–20
It may be helpful to write each term as a base to the 3rd power before using the factoring patterns for the sum and difference of cubes.

  1. 8y31

8y=2y3, 1=132y12y2+2y·1+12

2y14y2+2y+1

  1. 27c3+64

27c3=3c3, 64=433c+43c23c·4+42

3c+49c212c+16

  1. 250v3+16

2125v2+8; 125v3=5v3, 8=2325v+25v25v·2+22

25v+225v210v+4

  1. x3y3a3b3

x3y3=xy3, a3b3=ab3xyabxy2+xy·ab+ab2

xyabx2y2+abxy+a2b2

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