Practice 2 Solutions

  1. Write the equation of the ellipse with a center (0, 0), a horizontal major axis length of 5, and a minor axis length of 3.

Center: 0, 02a=5a=2.5a2=6.252b=3b=1.5b2=2.25

x26.25+y22.25=1

  1. Write the equation of the ellipse with a center 23.12, 98.54, when a=45 and b=23.

Center: 23.12, 98.54a=45a2=452=1625=16·5=80b=23b2=232=49=4·3=12

x+23.12280+y98.54212=1

  1. Write the equation of the ellipse with vertices (6, 4) and (10, 4), and co-vertices (2, 1) and (2, 7).

Center:6+102, 4+4 2=2, 42a=16a=8a2=642b=6b=3b2=9

x+2264+y+429=1

  1. Write the equation of the ellipse when it is translated 8 units to the left, 4 units up, and the major axis is increased by 2.

    x29+(y3)264=1

Center: 08, 3+4=8, 7a=32a = 6 minor axisb=82b=16 major axisNew major axis:16+2=18b=9

x+829+y7281=1

  1. Write the equation that translates the given graph 3 units right, 2 units down, and increases the minor radius by 3.

Center: 2, 1New center: 2+3, 12=1, 1a=5b=4 +3 = 7x1252+y+1272=1

x1225+y+1249=1

Note

Q: How does the transformation affect the major and minor axes?

A: The minor axis is now the major axis.

  1. Write the equation of the ellipse tangent to: x=12, x=0, y=14, y=0

Center: 6, 72a=12a=6a2=362b=14b=7b2=49

x+6236+y7249=1

  1. A domed building with an elliptical room measures 23 feet wide and 97 feet long. Write the equation of the footprint of the room centered at the origin.

Center:0, 02a=23a=12.5a2=156.252b=97b=48.5b2=2,352.25

x2156.25+y22,352.25=1

Note

It would also be correct if a=48.5 and b=12.5.

  1. The blueprint for an elliptical stadium shows the horizontal major axis with a length of 4 units and the minor axis length of 2 units. The building will be 20 times the scale of the blueprint. Write the equation of the constructed stadium centered at the origin. 

2a=4a=220a=202=402b=2b=120b=201=20

x21600+y2400=1

Write the equation in standard form.

  1. 100x2200x+225y2450y=22,175

100x22x+225y22y=22,175100x22x+222+225y22y+222=22,175+100222+225222100x12+225y12=22,175+100+225100x12+225y12=22,500

x12225+y12100=1

  1. 3x2+12x+8y248y=12

3x2+4x+8y26y=123x2+4x+422+8y26y+622=12+3422+86223x+22+8y32=12+34+893x+22+8y3=96

x+2232+y3212=1

  1. Explain how to determine if the ellipse is horizontal or vertical from an equation.

Sample: Determine the values of a and b from the equation. If a>b, then the major axis and the ellipse are horizontal. If b>a, then the major axis and the ellipse are vertical.

  1. Explain how to determine the length of the major and minor axis given the equation of the ellipse.

Sample: In the equation of an ellipse, the values of a and b are squared. To determine the axes, you need to take the square root of a and b. Then double each value to find the length of each axis.

Graph. Label the center, vertices, and co-vertices.

  1. x2232+y3212=1

Center: 2, 3a2=32a=32=425.657b2=12b=12=233.464

  1. x212.25+y4216=1

Center: 0, 4a2=12.25a=3.5b2=16b=4

  1. x+5225+y2225=1

Center: 5, 2a2=25a=5b2=25b=5

Note

Q: What is another name for this conic? 
A: Circle

  1. x264+y281=1

Center: 0, 0a2=64a=8b2=81b=9

  1. x+4210+y224=1

Center: 4, 0a2=10a=103.162b2=24b=264.899

  1. The center of an ellipse is translated 5 units right and 6 units down from (8, 4). The horizontal major axis is 17 units and the minor axis is 11 units.

Center: 8+5, 46=13, 22a=17a=8.5a2=72.252b=11b=5.5b2=30.25

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