Lesson 15: Complex Numbers and the Imaginary Unit

Warm Up Solutions

Simplify.

  1. 2x32x+3

4x22x3+2x33

4x23

  1.  x55÷x11

x5511

x44

Note

Remember to look at the Formula Sheet to review the exponent rules.


Q: What exponent rules reference division?

A: The Quotient Rules

  1. x84

x84

x32

  1. 4

no real solution

Note

Up to this point, you have only simplified problems involving real numbers.

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Explore

The Imaginary Unit i Solutions

  • The imaginary unit i is a special number in math that is unique because it does not have a    real number value  .
  • The imaginary unit i is defined as:   i2=1   
  • The number i is the principal square root of –1, or:    i=1   
  • Imaginary numbers can be    simplified     using the following guidelines:

Rules for the Imaginary Unit

i0=1

 

i=1 

 

i2=1

 

i3=i

i3=i·i2=i·1=i

i4=1 

i4=i22=12=1

  • When evaluating an expression using the number i, use the    exponent rules     to rewrite the base as i4 raised to a power because i4=1 will be easier to work with.
  • If there is a    remainder    , it determines if the answer will be i, –1, or –i.
Note

While you should have your Formula Sheet at all times, using it for this particular lesson will be very important. This lesson uses the exponent rules, algebraic properties, and the rules for the imaginary unit.

Example 1

Evaluate.

  1. i9i8·ii42·i12·i

i

  1. i10i8·i2i42·i2 

12·11

  1. i11i8·i3

i42·i312·ii

  1. i12

i4313=1

Note

Notice that a remainder determines the value. Dividing the exponent by 4 and then determining the remainder may be helpful when evaluating expressions with i.

Example 2

Evaluate.

  1. i39
      39÷4=9 R3i49·i3i

39÷4=9 R3i49·i3i

  1. i85

85÷4=21 R1i421·ii

  1. i46

i4646÷4=11 R2i411·i21

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Checkpoint: The Imaginary Unit 𝒊 Solution

Evaluate.

  1. i18

18÷4=4 R2i44·i21

Note

Q: By what number do you divide the exponent to simplify the imaginary unit? Explain.

A: 4, because i4=1

  1. i43

43÷4=10 R3i410·i3i

Note

Q: Why is it important to know the remainder when the number i is raised to a power?
A: Because this determines the value –1, –i, or i.

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Negative Square Roots Solutions

  • The rules to simplify radical expressions are only true when the radicands are    real numbers ℝ    .
  • However, because the number i is the principal square root of –1, or i=1 , problems that have a    negative     radicand can now be simplified using the    imaginary unit    .
  • Therefore,    –1     must be simplified out of the radicand first. Then the remaining radicand can be simplified, if possible. 
Note

In Algebra 1, you wrote “no real solution” for a result that included a square root with a negative radicand. While that is still true, now you can simplify the radicand using imaginary numbers. This will be discussed further in the next video.

Example 3

Simplify.

16 

Implement

1·24i·224i

Explain

  • Prime factorization
  • Simplify
Note

You can write –1 in the radicand or simplify it to i in your first step. Both are correct.

Example 4

Simplify.

12 

Implement

1·22·3 2i3

Explain

  • Prime factorization
  • Simplify

Example 5

Simplify.

 8·6 

Note

Be careful! It is tempting to multiply first here, but the rule for simplifying radicals only applies to real numbers.

Implement

i8·i6i224·314343

Explain

  • Simplify out 1 
  • Simplify i and radicands
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Checkpoint: Negative Square Roots Solutions

Simplify.

  1. 100

i10210i

  1. 33·3

i99i32·113i11

Note

Remember to simplify 1  from the radicand first. This becomes important to the next part of the lesson.

 

Q: Why are the answers so different when the radicands only have a difference of one?

A: Sample: Because 100 is a perfect square and 99 is not.

 

Q: If you multiplied A and B together, would the answer be positive or negative? Explain.

A: The answer would be negative because i2=1, which would be part of the coefficient.

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The Complex Number System Solutions

  • The complex number system consists of numbers in the form    a+bi   , where a and b are part of the     real    number system, or a, b.
  •    Complex numbers ℂ    includes the set of real numbers ℝ, and the set of imaginary numbers i.
  • The number i can only be combined with    like terms   , meaning other imaginary numbers.
  • This means that a real number and an imaginary number can only be written as an    expression   .
    •    Real numbers    are written as a+bi where b=0 (or a).
    •    Pure imaginary numbers    numbers are written as a+bi where a=0 (or bi).

Example 6

Classify by all sets to which it belongs: real, pure imaginary, complex. Then add A–D to the Complex Number diagram on the previous page.

  1. 15+3i

complex

  1. 8i

pure imaginary, complex

  1. 48+i2

real, complex

  1. 710i

complex

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Checkpoint: The Complex Number System Solution

Classify by all sets to which it belongs: real, pure imaginary, complex. Then add to the Complex Number diagram (in the guided notes).

  1. 26i 
    pure imaginary, complex

  1. 3 + 7i  
    complex

Note

Q: Are real numbers complex numbers? Are imaginary numbers complex numbers? Explain.

A: Both real and imaginary numbers are also complex numbers. You can see this in the diagram. It shows the real numbers and imaginary numbers inside the complex number box. 

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Practice 1 Solutions

Evaluate.

Note

Use the Formula Sheet to help with the rules for the imaginary unit i.

  1. i29

29÷4=7 R1i47·i1·i

i

  1. i75

75÷4=18 R3i418·i31·i

i

  1. i16

16÷4=4i44

1

  1. i50

50÷4=12 R2i412·i21·1

–1

  1. i120

120÷4=30i430

1

  1. i101

101÷4=25 R1i425·i1·i

i

  1. i38

38÷4=9 R2i49·i21·1

–1

  1. i67

67÷4=16 R3i416·i31·i

i

Simplify.

Note

Q: Why must the imaginary unit i be simplified out when the radicand is negative?

A: Because the rules to simplify radicals are only true for real numbers.

  1. 18

i32·2

3i2

  1. 36·16

i62·i426i·4i24i2

–24

Note

Remember to simplify out 1before multiplication of any radicands. If your answer is positive, you did not write 1as i in your first step.

  1. 54

i33·2

3i6

  1. 32

i25

4i2

  1. 144

i122

12i

  1. 310·735

3i2·5·7i5·721i252·2·7105i214

10514

Note

Q: What is another way to write i2?

A: Negative one.

  1. 281·24

2i92·i23·318i·2i636i26

366

  1. 98

i72·2

7i2

Simplify. Then classify by all sets to which it belongs: real, pure imaginary, complex.

Note

Q: What classification can you use for every number?

A: Complex


Q: Why is it a good math practice to simplify before you classify numbers?

A: Because the simplified answer may not be the exact classification you originally expected.

  1. 12

23

Real, complex

  1. 16+8

4+2i2

Complex

  1. 121

11i

Pure imaginary, complex

  1. 5+49

5+712

Real, complex

  1. 3i

Pure imaginary, complex

  1. 25

5i

Pure imaginary, complex

  1. 49·4

7i·2i14i214114

Real, complex

  1. 139

133i

Complex

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Mastery Check Solutions

Show What You Know

Complete the statement with always, sometimes, or never.
If your answer is sometimes or never, provide an example to back up your choice.

  1. The imaginary unit i raised to a whole number power is    sometimes    a pure imaginary number.

Sample: i1= i ,  i2=1 ,  i3= i  , and i4=1. The numbers –1 and 1 are real, not imaginary, while i and i are pure imaginary.

  1. Complex numbers    always    include the sets of real and imaginary numbers.
  1. The square root of a negative number is    never    a real number.

Sample:1=i, where i is an imaginary number.

  1. Complex numbers are    sometimes    classified as real, complex numbers.

Sample: a + bi, when a=0 is pure imaginary. If an expression is in the form a+bi, this is complex only. If an expression is in the form a+bi, when b=0, the number is real, complex.

Note

These statements should help you think about how the imaginary numbers work within the complex number system. There are many examples you can share for A, C, and D. If you are not certain, use the Practice page to find specific examples.

Say What You Know

In your own words, talk about what you have learned using the objectives for this part of the lesson and your work on this page.

Note

Restate the objectives of the lesson in your own words. If you are unable to restate the lesson objectives, go back and reread the objectives and then explain them.

    • Classify complex numbers (real, imaginary, complex).
    • Define the imaginary unit as i2=1.
    • Simplify roots of negative numbers using the imaginary unit.
    • Use the pattern of i to simplify powers of the imaginary unit.
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Practice 2 Solutions

Evaluate.

  1. i2

–1

  1. i78

78÷4=19 R2i419·i21·1

–1

  1. i15

15÷4=3 R3i43·i31·i

i

  1. i10

10÷4=2 R2i42·i21·1

–1

  1. i61

61÷4=15 R1i415·i1·i

i

  1. i99

99÷4=24 R3i424·i31·i

i

Simplify.

  1. 35·24

3i5·2i223i5·4i12i25

125

  1. 640

6i23·5

12i10

  1. 12·3

i22·3·i3i222·326i2

–6

  1. 196

i142

14i

  1. 207·14

20i7·i2·720i272·2140i22

1402

  1. 64

i82

8i

Simplify. Then classify by all sets to which it belongs: real, pure imaginary, complex.

  1. 4

2i

Pure imaginary, complex

  1. 49·100

i49·i1007i·10i70i270170

Real, complex

  1. 550·8

552·2i2252·2i250i2250i2100i

Pure imaginary, complex

  1. 9·81

3i·9i27i227

Real, complex

  1. 12120

112i5

Complex

  1. 45

3i5

Pure imaginary, complex

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Targeted Review Solutions

Simplify.

  1. 35x·15x3

5·7·3·5·x4312·522·712·x42

5x221

  1. 10+78+127

10+78127 

2117

  1. 2+510+6

2+510+61061062026+105301006

2026+1053094

Solve.

  1. x+33=3

x+333=33x+3=27

x=24

  1. x+57

x2x222

x4

  1. 2x3<7

2x30x1.5   principal root2x32<722x3<492x<52x<26

1.5x<26

Graph.

  1. y=43x2

m=43, b=2

  1. y=1x32

asymptotes: x=3, y=2a=1

Multiple Choice

A

  1. Simplify. 48x8y33
  1. 2x2y6x23

  2. 2x2y3x23

  3. 4x4y23y3

  4. 16x2yx23

     

    243313x83y332113313x223y12x2y6x23

Note
  1. The coefficient of the radicand is missing a factor of 2.

  1. This option uses an index of 2 rather than 3.

  1. This option divides 48 by 3 rather than using the prime factorization and exponent rules.

C

  1. Solve. 3x16=2
  1. 13

  2. 5

  3. 173

  4. no solution

     

    3x1=43x12=423x1=163x=17x=173

Note
  1. This option represents the restriction of the principal root.

  1. This option occurs if 1 is subtracted rather than added to both sides.

  1. The radical needs to be isolated on one side before determining if there is no solution.

C

  1. Name the range using the graph of the rational function.
  1. y|y, y1

  2. y|y, y0

  3. y|y, y4

  4. y|y, y5

Note
  1.  –1 represents the restriction on the domain.

  1. This option is the x-axis, and not a restriction for the range.

  1. This option is the value of the y-intercept.

B

  1. Determine the equation that best represents the linear function.
  1. y=14x+2

  2. y=14x+2

  3. y=15x+2

  4. y=15x+2

Note

A, D) The slope of the graph is negative. 

C, D) Using 4, 3 and 0, 2, the slope is 14.

Problem123456789101112
OriginL11L12L12L13L14L14A1L10L11L13L10A1

L = Lesson in this level, A1 = Algebra 1: Principles of Secondary Mathematics, FD = Foundational Knowledge

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