Warm-Up Solutions

Simplify. Do not use a calculator.

${(\sqrt[4]{81})}^{3} {(3)}^{3} 27$

${(\sqrt[5]{32})}^{- 2} {(2)}^{- 2} = \frac{1}{2^{2}} \frac{1}{4}$

Note

Q: What is the first step to simplifying a base raised to a fractional exponent?

A: Rewrite the expression with the denominator as the index of the radical.