Targeted Review Solutions

  1. x+52x3+15

2x2x3+2x515+15

2x2x3+2x5

  1. i36i17

i49i44i1914i

i

  1. 2+3i7i3

142i3+21i3i4142i+21i3114+2i+21i3

11 + 23i

  1. y3+x

y3+x3x3x

3yyx9x

  1. Describe the end behavior for the function: mx=x82

a=1, h=8, k=2

As x, mx, and as x8, mx2

Solve. Graph solutions on a number line.

  1. x+53x

RestrictionsSolvex+50x53x0x3x+523x2x+53x2x2x1

  1. x>2x+3

RestrictionsSolve2x+30x2>2x+322x3x2>2x+3x1.5x22x3>0x3x+1>0x>3     x>1

  1. Name the domain and range of the absolute value parent function in set builder notation.

domain: x|x, range: y|y, y0

Multiple Choice

B

  1. Which type of equation would best represent the given graph?
  1. absolute value

  2. cubic

  3. square root

  4. quadratic

     

    no work is needed for this problem

Note

A, C, D) These equations do not represent the shape of the given graph.

C

  1. Choose the best description of the transformation of the quadratic parent function for the equation:
    qx=2x+8211
     
  1. The graph is vertically stretched by a factor of 2, moved 8 spaces left, and 11 spaces down from the parent graph.

  2. The graph is vertically compressed by a factor of 2, moved 8 spaces right, and 11 spaces down from the parent graph.

  3. The graph is vertically compressed by a factor of 2, moved 8 spaces left, and 11 spaces down from the parent graph.

  4. The graph is vertically stretched by a factor of 2, moved 8 spaces right, and 11 spaces down from the parent graph.

     

    no work needed for this problem

Note

A, D) The graph is compressed because a=2

B, D) The graph moves left 8 spaces because h=8

B

  1. Find the perimeter of a rectangle with a length of 6x+7 units and a width of 4x1 units.
  1. 10x + 6 units

  2. 20x + 12 units

  3. 24x2+22x7 square units

  4. 20x + 12 square units

     

    P=2l+wP=26x+7+4x1P=210x6P=20x+12

Note
  1. This option is the sum before multiplying by two.
  2. This option is the area of the rectangle and perimeter is not in square units.
  3. This option is not possible because the perimeter is not in square units.

D

  1. Solve: 5x+11>1
  1.  

Note
  1. This option is the solution if the negative sign in the given inequality is ignored.
  2. This option is the solution if both cases of the inequality are solved. However, none of the values will make the inequality true.
  3. This option is not possible, no value makes this true.

5x+11<1

No solution, absolute value cannot be less than a negative number.

Problem 1 2 3 4 5 6 7 8 9 10 11 12
Origin L12 L15 L16 L12 L18 L14 L14 L17 L17 L18 A1 A1

L = Lesson in this level, A1 = Algebra 1: Principles of Secondary Mathematics, FD = Foundational Knowledge

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