Checkpoint: Remainder Theorem for Polynomials Solution
Find the value of n for P(6) = 5 for .

Note
Q: What is the value (or zero of the divisor) you are using for synthetic division?
A: 6
Q: What value belongs in the remainder space?
A: 5
You need to complete the steps for synthetic division before an equation can be set up to solve for the value of n.